What does heating and decomposing do to a chemical equation?
Calcium oxide is prepared by heating and decomposing calcium carbonate. How much of the carbonate would be required to produce 15 grams of the oxide? The answer is supposed to be approx. 26.8 grams, but how do you do the work to get this answer?
CaCO3 = CaO + CO2
moles CaO = 15 g / 56 g/mol=0.268
moles CaCO3 = 0.268
mass CaCO3 = 0.268 mol x 100 g/mol= 26.8 g